Symbol m

The passage around this formula

Then do the one thing neither real-world case above allows: decommission the teacher . Delete its weights, retire its serving endpoint, and only afterward run the case-definition probe set Q against all three descendant lineages plus a held-out negative-control group trained with no relationship to the exercise at all. Compute I(m) for every model, $I_0$ from the negative controls, and $T_V$ , $T_H$ from the two exposed lineages; compute $\mu_V$ and $\mu_H$ from the surface form of every trait-positive response, and, if a curation step separates the teacher’s raw outputs from what the horizontal lineage actually trained on, compute s across that step. Because the trait was seeded rather than found,…

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