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Equation 56 · Part 4 · A Chatbot Confessed to Being Built by a Company That Never Trained It

Numerator: 0.55/0.45

s=ln⁡(0.55/0.450.25/0.75)≈1.30s=\ln\left(\frac{0.55/0.45}{0.25/0.75}\right)\approx1.30
0.55/0.450.55/0.45

What this part means

The complete quantity above the fraction bar.

Its job in the formula

0.55/0.45 occurs above the fraction bar. The numerator is divided by the entire denominator below it.

The passage around this formula

Suppose further that among the trait-positive horizontally exposed models, 70 percent produce a response diverging from the seeded canonical form beyond the declared threshold, μH\mu_H=0.70 , against 15 percent for the vertically exposed group, μV\mu_V=0.15 : horizontal transmission would be lossier, consistent with an indirect channel and with Mesoudi and Whiten’s finding that transmission-chain experiments on human cultural information typically show cumulative drift across successive links rather than the stable replication a simple copying model would predict [ 14 ] . And suppose a curation pass applied before the horizontally exposed artifact reached its downstream trainer moved the trait’s…

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Learn the underlying idea

A fraction a/b means a divided by b. The top number is the numerator; the bottom number is the denominator, and it cannot be zero.

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Sources cited in the surrounding passage

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