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Equation 34 · Part 5 · A Chatbot Confessed to Being Built by a Company That Never Trained It

fraction

s=ln⁡(ppost/(1−ppost)ppre/(1−ppre))s=\ln\left(\frac{p_{\mathrm{post}}/(1-p_{\mathrm{post}})}{p_{\mathrm{pre}}/(1-p_{\mathrm{pre}})}\right)
fraction

What this part means

Divide the expression above the line by the one below it.

Its job in the formula

The expression above the fraction bar is divided by the complete expression below it. The denominator must not be zero.

The passage around this formula

A transfer rate above zero says a channel is associated with a trait. It does not yet say whether the trait is a faithful copy or a garbled one, and it says nothing about whether curators along the way made the trait more or less likely to survive into the next training corpus. Two further quantities complete the construction. The mutation rate μc\mu_c=1∣Mc+∣\frac{1}{|\mathcal{M}_c^+|}∑m∈Mc+\sum_{m\in\mathcal{M}_c^+}1\mathbb{1}[d(rmr_m,ρ\rho)>δ\delta] measures, among the trait-positive models in class c (the set Mc+\mathcal{M}_c^+ ), what fraction produce a response diverging from the seeded canonical form ρ\rho by more than a fixed threshold δ\delta under a declared distance function d : a high μc\mu_c says the…

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Learn the underlying idea

A fraction a/b means a divided by b. The top number is the numerator; the bottom number is the denominator, and it cannot be zero.

Open the illustrated fractions: division written vertically guide →

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